# Problem: Diamond and graphite are two crystalline forms of carbon. At 1 atm and 25°C, diamond changes to graphite so slowly that the enthalpy change of the process must be obtained indirectly. Using equations from the list below, determine ΔH  for C(diamond) ⟶ C(graphite)(1) C(diamond) + O2(g) ⟶ CO2(g)          ΔH = −395.4 kJ(2) 2CO2(g) ⟶ 2CO(g) + O2(g)              Δ H = 566.0 kJ(3) C(graphite) + O2(g) ⟶ CO2(g)          Δ H = −393.5 kJ(4) 2CO(g) ⟶ C(graphite) + CO2(g)      ΔH = −172.5 kJ

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###### Problem Details

Diamond and graphite are two crystalline forms of carbon. At 1 atm and 25°C, diamond changes to graphite so slowly that the enthalpy change of the process must be obtained indirectly. Using equations from the list below, determine ΔH  for

C(diamond) ⟶ C(graphite)
(1) C(diamond) + O2(g) ⟶ CO2(g)          ΔH = −395.4 kJ
(2) 2CO2(g) ⟶ 2CO(g) + O2(g)              Δ H = 566.0 kJ
(3) C(graphite) + O2(g) ⟶ CO2(g)          Δ H = −393.5 kJ
(4) 2CO(g) ⟶ C(graphite) + CO2(g)      ΔH = −172.5 kJ

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What professor is this problem relevant for?

Based on our data, we think this problem is relevant for Professor Waddell's class at UC.

What textbook is this problem found in?

Our data indicates that this problem or a close variation was asked in Chemistry: The Molecular Nature of Matter and Change - Silberberg 8th Edition. You can also practice Chemistry: The Molecular Nature of Matter and Change - Silberberg 8th Edition practice problems.