Problem: A monoprotic acid, HA, is dissolved in water HA ⇌ H+ + A- The equilibrium concentrations of the reactants and products are HA 0.150 M [H+] = 3.00 × 10-4 M[A-] = 3.00 × 10-4 M Calculate the value of pka for the acid HA. 

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Ka or acid dissociation constant can be expressed using the reaction equation as:

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Problem Details

A monoprotic acid, HA, is dissolved in water 

HA ⇌ H+ + A- 

The equilibrium concentrations of the reactants and products are 

HA 0.150 M 

[H+] = 3.00 × 10-4 M

[A-] = 3.00 × 10-4

Calculate the value of pka for the acid HA. 

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