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Calcium hydroxide, which reacts with carbon dioxide to form calcium carbonate, was used by the ancient Romans as mortar in stone structures. The reaction for this process is
Ca(OH)2 (s) + CO2 (g) → CaCO3 (s) + H2O (g) ΔH = -69.1 kJ
What is the enthalpy change if 3.8 mol of calcium carbonate is formed?
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Based on our data, we think this problem is relevant for Professor Saidane's class at San Diego Mesa College.