Ch.15 - Acid and Base EquilibriumWorksheetSee all chapters
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Ch.1 - Intro to General Chemistry
Ch.2 - Atoms & Elements
Ch.3 - Chemical Reactions
BONUS: Lab Techniques and Procedures
BONUS: Mathematical Operations and Functions
Ch.4 - Chemical Quantities & Aqueous Reactions
Ch.5 - Gases
Ch.6 - Thermochemistry
Ch.7 - Quantum Mechanics
Ch.8 - Periodic Properties of the Elements
Ch.9 - Bonding & Molecular Structure
Ch.10 - Molecular Shapes & Valence Bond Theory
Ch.11 - Liquids, Solids & Intermolecular Forces
Ch.12 - Solutions
Ch.13 - Chemical Kinetics
Ch.14 - Chemical Equilibrium
Ch.15 - Acid and Base Equilibrium
Ch.16 - Aqueous Equilibrium
Ch. 17 - Chemical Thermodynamics
Ch.18 - Electrochemistry
Ch.19 - Nuclear Chemistry
Ch.20 - Organic Chemistry
Ch.22 - Chemistry of the Nonmetals
Ch.23 - Transition Metals and Coordination Compounds

Solution: Ba(OH)2 is a strong electrolyte. Determine the concentration of each of the individual ions in a 0.750 M Ba(OH)2 solution.[Ba2+][OH-]

Solution: Ba(OH)2 is a strong electrolyte. Determine the concentration of each of the individual ions in a 0.750 M Ba(OH)2 solution.[Ba2+][OH-]

Problem

Ba(OH)2 is a strong electrolyte. Determine the concentration of each of the individual ions in a 0.750 M Ba(OH)2 solution.

[Ba2+]

[OH-]


Solution

We’re being asked to calculate the individual ion concentration in a 0.750 M Ba(OH)2 solution.


Let’s first determine what type of base is Ba(OH)2:

Any Group 2A metal (from Ca2+ to Ba2+when combined with OH-, H-, O2- or NH2- makes a strong base

Ba (Group 2A metal) is paired with OH-

Ba(OH)2strong base

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