Chemistry Practice Problems Hess's Law Practice Problems Solution: Research is being carried out on cellulose as a so...

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Solution: Research is being carried out on cellulose as a source of chemicals for the production of fibers, coatings and plastics. Cellulose consists of long chains of glucose molecules (C6H12O6), so for the purposes of modeling the reaction we can consider the conversion of glucose to formaldehyde (H2CO). Calculate the heat of reaction for the conversion of 1 mole of glucose into formaldehyde, given the following thermochemical data:H2CO (g) + O2 (g) → CO2 (g) + H2O (g)     ΔH°comb = -572.9 kJ/mol 6C (s) + 6H2 (g) + 3O2 (g) → C6H12O6 (s)     ΔH°f = -1274.4 kJ/mol C (s) + O2 (g) → CO2 (g)     ΔH°f = -393.5 kJ/mol H2 (g) + 1/2O2 (g) → H2O (g)     ΔH°f = -285.8 kJ/mol C6H12O6 (s) → 6H2CO (g)     ΔH°rxn = ?

Problem

Research is being carried out on cellulose as a source of chemicals for the production of fibers, coatings and plastics. Cellulose consists of long chains of glucose molecules (C6H12O6), so for the purposes of modeling the reaction we can consider the conversion of glucose to formaldehyde (H2CO). 

Calculate the heat of reaction for the conversion of 1 mole of glucose into formaldehyde, given the following thermochemical data:

H2CO (g) + O2 (g) → CO(g) + H2O (g)     ΔH°comb = -572.9 kJ/mol 

6C (s) + 6H2 (g) + 3O2 (g) → C6H12O(s)     ΔH°f = -1274.4 kJ/mol 

C (s) + O2 (g) → CO2 (g)     ΔH°f = -393.5 kJ/mol 

H2 (g) + 1/2O2 (g) → H2O (g)     ΔH°f = -285.8 kJ/mol 

C6H12O6 (s) → 6H2CO (g)     ΔH°rxn = ?

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