Solution: A sample of helium gas occupies a volume of 161.0 mL at a pressure of 712.0 mm Hg and a temperature of 306.0 K. What will the volume be at a pressure of 474.0 mm Hg and a temperature of 804.0 K? The combined gas law equation is given below. P1V1/T1 = P2V2/T2 In this equation, P1, V1, and T1 are the initial pressure, volume, and temperature, respectively, and P2, V2, and T2 are the final pressure, volume, and temperature, respectively.

Problem

A sample of helium gas occupies a volume of 161.0 mL at a pressure of 712.0 mm Hg and a temperature of 306.0 K. What will the volume be at a pressure of 474.0 mm Hg and a temperature of 804.0 K? The combined gas law equation is given below. 

P1V1/T1 = P2V2/T2 

In this equation, P1, V1, and T1 are the initial pressure, volume, and temperature, respectively, and P2, V2, and T2 are the final pressure, volume, and temperature, respectively.

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