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Find ΔH° for BaCO3 (s) → BaO (s) + CO2 (g) given that
2Ba (s) + O2 (g) → 2BaO (s) ΔH° = -1107.0 kJ
Ba (s) + CO2 (g) + 1/2O2 (g)→ BaCO3 (s) ΔH° = - 822.5 kJ
a. -1929.5 kJ
b. -1376.0 kJ
c. -284.5 kJ
d. 269.0 kJ
e. 537 kJ
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