Ch.13 - Chemical KineticsWorksheetSee all chapters
All Chapters
Ch.1 - Intro to General Chemistry
Ch.2 - Atoms & Elements
Ch.3 - Chemical Reactions
BONUS: Lab Techniques and Procedures
BONUS: Mathematical Operations and Functions
Ch.4 - Chemical Quantities & Aqueous Reactions
Ch.5 - Gases
Ch.6 - Thermochemistry
Ch.7 - Quantum Mechanics
Ch.8 - Periodic Properties of the Elements
Ch.9 - Bonding & Molecular Structure
Ch.10 - Molecular Shapes & Valence Bond Theory
Ch.11 - Liquids, Solids & Intermolecular Forces
Ch.12 - Solutions
Ch.13 - Chemical Kinetics
Ch.14 - Chemical Equilibrium
Ch.15 - Acid and Base Equilibrium
Ch.16 - Aqueous Equilibrium
Ch. 17 - Chemical Thermodynamics
Ch.18 - Electrochemistry
Ch.19 - Nuclear Chemistry
Ch.20 - Organic Chemistry
Ch.22 - Chemistry of the Nonmetals
Ch.23 - Transition Metals and Coordination Compounds

Solution: Phosgene is formed by the reaction of Cl 2 and CO. The experimental rate law is  Rate = k [CO][Cl2]3/2. The proposed reaction mechanism is  Cl2(g) ⇌ 2Cl(g)                                       Step 1 Cl(g) + CO(g) ⇌ ClCO(g)                       Step 2 ClCO(g) + Cl2(g) → Cl2CO(g) + Cl(g)     Step 3 For the proposed reaction mechanism to be consistent with the rate law: a) Step 1 is slow and Steps 2 and 3 are fast b) Step 3 is fast and steps 1 and 2 are slow c) Steps 1 and 2 are fast and step 3 is slow d) Steps 1 and 3 are fast and step 2 is slow e) Step 1 is fast and steps 2 and 3 are slow

Solution: Phosgene is formed by the reaction of Cl 2 and CO. The experimental rate law is  Rate = k [CO][Cl2]3/2. The proposed reaction mechanism is  Cl2(g) ⇌ 2Cl(g)                                       Ste

Problem

Phosgene is formed by the reaction of Cl 2 and CO. The experimental rate law is 

Rate = k [CO][Cl2]3/2.

The proposed reaction mechanism is 

Cl2(g) ⇌ 2Cl(g)                                       Step 1

Cl(g) + CO(g) ⇌ ClCO(g)                       Step 2

ClCO(g) + Cl2(g) → Cl2CO(g) + Cl(g)     Step 3

For the proposed reaction mechanism to be consistent with the rate law:

a) Step 1 is slow and Steps 2 and 3 are fast

b) Step 3 is fast and steps 1 and 2 are slow

c) Steps 1 and 2 are fast and step 3 is slow

d) Steps 1 and 3 are fast and step 2 is slow

e) Step 1 is fast and steps 2 and 3 are slow