Problem: The combustion reaction of butane is as follows. C4H10(g) + 13/2 O2(g) → 4 CO2(g) + 5 H2O(l) Using Hess's law and the reaction enthalpies given below, find the change in enthalpy for this reaction. reaction (1):    C(s) + O2(g) → CO2(g)                               ΔH = -393.5 kJ/mol reaction (2):   H2(g) + 1/2 O2(g) → H2O(I)                        ΔH = -285.8 kJ/mol reaction (3):   4C(s) + 5H2(g) → C4H10 (g)                       ΔH = -125.7 kJ/mol

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The combustion reaction of butane is as follows. 

C4H10(g) + 13/2 O2(g) → 4 CO2(g) + 5 H2O(l) 

Using Hess's law and the reaction enthalpies given below, find the change in enthalpy for this reaction. 

reaction (1):    C(s) + O2(g) → CO2(g)                               ΔH = -393.5 kJ/mol 

reaction (2):   H2(g) + 1/2 O2(g) → H2O(I)                        ΔH = -285.8 kJ/mol 

reaction (3):   4C(s) + 5H2(g) → C4H10 (g)                       ΔH = -125.7 kJ/mol