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Use the standard reaction enthalpies given below to determine ∆Hrxn for the following reaction
P4 (g) + 10 Cl2(g) ---> 4PCI5(s) ∆Hrxn = ?
PCI5(s) --> PCl5(s) + Cl2(g) ∆Hrxn = +157 kJ
P4(g) + 6 Cl2(g) --> 4 PCl3(g) ∆Hrxn = -1207 kJ
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