Problem: What is the Kw of pure water at 50 degrees C, if the pH is 6.630?

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We’re being asked to determine the value of Kw for pure water at 50 ˚C given a pH of 6.630.


Recall that Kw is the autoionization constant of water, and is given by:


Kw=H+OH-


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What is the Kw of pure water at 50 degrees C, if the pH is 6.630?

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Our tutors have indicated that to solve this problem you will need to apply the Ka and Kb concept. You can view video lessons to learn Ka and Kb. Or if you need more Ka and Kb practice, you can also practice Ka and Kb practice problems.

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Based on our data, we think this problem is relevant for Professor TBA's class at UBC.