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A diprotic acid reacting with NaOH will appear as:
H2A + 2NaOH --> 2H2O + Na2A
From the diagram, 25 mL of base (NaOH) has been added to reach the endpoint
The flask shown here contains 0.365 g of acid and a few drops of phenolphthalein indicator dissolved in water. The buret contains 0.220 M NaOH.
What volume (mL) of base is needed to reach the end point of the titration?
What is the molar mass (g/mol) of the acid (assuming it is diprotic and that the end point corresponds to the second equivalence point)?
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Our tutors have indicated that to solve this problem you will need to apply the Titrations of Diprotic and Polyprotic Acids concept. You can view video lessons to learn Titrations of Diprotic and Polyprotic Acids. Or if you need more Titrations of Diprotic and Polyprotic Acids practice, you can also practice Titrations of Diprotic and Polyprotic Acids practice problems.
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Based on our data, we think this problem is relevant for Professor Owuor's class at ULL.