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We are being asked to find the volume of 0.18 M H2SO4 can be prepared by diluting 143 mL of 5.5 M H2SO4.
When we are adding water (or solvent) to a solution to decrease its concentration, we are diluting the solution. When dealing with dilution we will use the following equation:
M1 = initial concentration
V1 = initial volume
M2 = final concentration
V2 = final volume
Calculate the final volume of the 0.18 M H2SO4 solution.
What volume (L) of 0.18 M H2SO4 can be prepared by diluting 143 mL of 5.5 M H2SO4 ?
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Based on our data, we think this problem is relevant for Professor Buckley's class at WSU.