Problem: Given that Kb for (CH3)3N is 6.3 × 10-5 at 25°C, what is the value of Ka for (CH3)3NH+ at 25 °C?

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We are asked to find Ka for (CH3)3NH+. (CH3)3NH+ is the conjugate acid of the weak base (CH3)3NH.

(CH3)3NH     +     H2O      ⇌      (CH3)3NH+     +     OH-
(weak base)              (acid)             (conjugate acid)     (conjugate base) 

Hence, the Ka of (CH3)3NH+ can be calculated from the Kb of (CH3)3NH. Ka and Kb are connected by the autoionization constant of water (Kw) by the following equation:

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Given that Kb for (CH3)3N is 6.3 × 10-5 at 25°C, what is the value of Ka for (CH3)3NH+ at 25 °C?

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