Ch.15 - Acid and Base EquilibriumWorksheetSee all chapters
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Ch.1 - Intro to General Chemistry
Ch.2 - Atoms & Elements
Ch.3 - Chemical Reactions
BONUS: Lab Techniques and Procedures
BONUS: Mathematical Operations and Functions
Ch.4 - Chemical Quantities & Aqueous Reactions
Ch.5 - Gases
Ch.6 - Thermochemistry
Ch.7 - Quantum Mechanics
Ch.8 - Periodic Properties of the Elements
Ch.9 - Bonding & Molecular Structure
Ch.10 - Molecular Shapes & Valence Bond Theory
Ch.11 - Liquids, Solids & Intermolecular Forces
Ch.12 - Solutions
Ch.13 - Chemical Kinetics
Ch.14 - Chemical Equilibrium
Ch.15 - Acid and Base Equilibrium
Ch.16 - Aqueous Equilibrium
Ch. 17 - Chemical Thermodynamics
Ch.18 - Electrochemistry
Ch.19 - Nuclear Chemistry
Ch.20 - Organic Chemistry
Ch.22 - Chemistry of the Nonmetals
Ch.23 - Transition Metals and Coordination Compounds

Solution: Given that Ka for HClO is 4.0 x 10-8 at 25°C, What is the value of Kb for ClO- at 25°C? Kb =____? 

Solution: Given that Ka for HClO is 4.0 x 10-8 at 25°C, What is the value of Kb for ClO- at 25°C? Kb =____? 

Problem

Given that Ka for HClO is 4.0 x 10-8 at 25°C, What is the value of Kb for ClO- at 25°C? Kb =____? 

Solution

We are being asked to find Kb for ClO-. ClO- is the conjugate base of the weak acid HClO.

    HClO   +      H2O            ClO-      +        H3O+ 
(weak acid)         (base)        (conjugate base)     (conjugate acid) 

Hence, the Kb of ClO- can be calculated from the Ka of HClO.  Ka and Kb are connected by the autoionization constant of water (Kw) in the following equation:

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