Problem: The aqueous reaction of KOH with HBr is:KOH(aq) + HBr(aq) → KBr(aq) + H2O(l)At the start of such a reaction, the concentration of KOH(aq) is 0.275M. After 3.05 seconds the concentration is observed to be 0.0557M KOH(aq).What is the rate of the reaction? 

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FREE Expert Solution

KOH(aq) + HBr(aq) → KBr(aq) + H2O(l)


Recall that for a reaction aA  bB, the rate of a reaction is given by:


Rate=-1aΔ[A]Δt=1bΔ[B]Δt


where:

Δ[A] = change in concentration of reactants or products (in mol/L or M), [A]final – [A]initial

Δt = change in time, tfinal – tinitial




Since KOH is a reactant, the rate with respect to KOH is negative (–) since we’re losing reactants.



The rate of the reaction is:

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Problem Details

The aqueous reaction of KOH with HBr is:

KOH(aq) + HBr(aq) → KBr(aq) + H2O(l)

At the start of such a reaction, the concentration of KOH(aq) is 0.275M. After 3.05 seconds the concentration is observed to be 0.0557M KOH(aq).

What is the rate of the reaction?

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What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Average Rate of Reaction concept. You can view video lessons to learn Average Rate of Reaction. Or if you need more Average Rate of Reaction practice, you can also practice Average Rate of Reaction practice problems.

What professor is this problem relevant for?

Based on our data, we think this problem is relevant for Professor Habel Rodriguez's class at UNM.