🤓 Based on our data, we think this question is relevant for Professor Addo-Mensah's class at TAMIU.

A certain substance has a heat of vaporization of 47.70 kJ/mol. At what kelvin temperature will the vapor pressure be 3.50 times higher than it was at 293K?

We’re being asked to **determine the temperature** at which the **vapor pressure is 3.50 times higher** than it was at **293 K**, given the **heat of vaporization**.

For this problem, we can use the ** Clausius-Clapeyron Equation**:

where:

**P _{1}** = vapor pressure at T

**P _{2}** = vapor pressure at T

**ΔH _{vap}** = heat of vaporization (in J/mol)

**R** = gas constant (8.314 J/mol•K)

**T _{1} and T_{2}** = temperature (in K).

Clausius-Clapeyron Equation

Clausius-Clapeyron Equation

Clausius-Clapeyron Equation

Clausius-Clapeyron Equation