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Solution: The combustion of octane, C8H18, proceeds according to the reaction: 2 C8H18(l) + 25 O2(g) → 16 CO2(g) + 18 H2O(l) If 402 mol of octane combusts, what volume of carbon dioxide is produced at 14.0 °C and 0.995 atm?    

Problem

The combustion of octane, C8H18, proceeds according to the reaction:


2 C8H18(l) + 25 O2(g) → 16 CO2(g) + 18 H2O(l)

If 402 mol of octane combusts, what volume of carbon dioxide is produced at 14.0 °C and 0.995 atm?