Problem: Calculate ΔHrxn for the following reaction2 NOCl (g) → N2 (g) + 02 (g) + Cl2 (g)Given the following set of reactions;1/2 N2 (g) + 1/2 02 (g) → NO (g)          ΔH= 90.3KJNO (g) + 1/2 Cl2 (g) → NOCl (g)          ΔH = - 38.6 KJ

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FREE Expert Solution

We’re being asked to determine the enthalpy change (ΔHrxn) for the chemical reaction:


2 NOCl (g) → N(g) + O(g) + Cl(g)


We can use Hess’s Law to determine the enthalpy change of the overall reaction from the given reactions:


1. 1/2 N(g) + 1/2 O(g) → NO (g)          ΔH = 90.3KJ
2. NO (g) + 1/2 Cl(g) → NOCl (g)           ΔH = - 38.6 KJ


We now need to find a combination of reactions that when added up, gives us the overall reaction.


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Problem Details

Calculate ΔHrxn for the following reaction

2 NOCl (g) → N(g) + 0(g) + Cl(g)

Given the following set of reactions;

1/2 N(g) + 1/2 0(g) → NO (g)          ΔH= 90.3KJ
NO (g) + 1/2 Cl(g) → NOCl (g)          ΔH = - 38.6 KJ