# Problem: At 0 degrees C, the ion product constant of water is 1.2x10 –15. The pH of pure water at this temperature is:6.887.007.467.56

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###### FREE Expert Solution

We’re being asked to determine the pH of pure water at 0 ˚C, given a Kw of 1.2 × 10–15.

Recall that Kw is the autoionization constant of water, and is given by:

$\overline{){{\mathbf{K}}}_{{\mathbf{w}}}{\mathbf{=}}\left[{\mathbf{H}}^{\mathbf{+}}\right]\left[{\mathbf{OH}}^{\mathbf{-}}\right]}$

###### Problem Details

At 0 degrees C, the ion product constant of water is 1.2x10 –15. The pH of pure water at this temperature is:

1. 6.88
2. 7.00
3. 7.46
4. 7.56