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Solution: Determine the theoretical yield of K2CO3 when 0.392 moles of KO2 react with 29.0 L of CO2 (at STP - 0°C, 1 atm). The molar mass of KO 2 = 71.10 g/mol and K2CO3 = 138.21 g/mol. 4 KO2(s) + 2 CO2(g) → 2 K2CO3(s) + 3 O2(g) a) 27.1 gb) 179 gc) 91.7 gd) 206 ge) 61.0 g 

Problem

Determine the theoretical yield of K2CO3 when 0.392 moles of KO2 react with 29.0 L of CO2 (at STP - 0°C, 1 atm). The molar mass of KO 2 = 71.10 g/mol and K2CO3 = 138.21 g/mol.

 

4 KO2(s) + 2 CO2(g) → 2 K2CO3(s) + 3 O2(g)

 

a) 27.1 g

b) 179 g

c) 91.7 g

d) 206 g

e) 61.0 g