All Chapters
Ch.1 - Intro to General Chemistry
Ch.2 - Atoms & Elements
Ch.3 - Chemical Reactions
BONUS: Lab Techniques and Procedures
BONUS: Mathematical Operations and Functions
Ch.4 - Chemical Quantities & Aqueous Reactions
Ch.5 - Gases
Ch.6 - Thermochemistry
Ch.7 - Quantum Mechanics
Ch.8 - Periodic Properties of the Elements
Ch.9 - Bonding & Molecular Structure
Ch.10 - Molecular Shapes & Valence Bond Theory
Ch.11 - Liquids, Solids & Intermolecular Forces
Ch.12 - Solutions
Ch.13 - Chemical Kinetics
Ch.14 - Chemical Equilibrium
Ch.15 - Acid and Base Equilibrium
Ch.16 - Aqueous Equilibrium
Ch. 17 - Chemical Thermodynamics
Ch.18 - Electrochemistry
Ch.19 - Nuclear Chemistry
Ch.20 - Organic Chemistry
Ch.22 - Chemistry of the Nonmetals
Ch.23 - Transition Metals and Coordination Compounds

Solution: The barometeric pressure was 749 mmHg when the open end manometer attached to a flask holding a gas read 13.0 mmHg. (mercury level highest on the side connected to the flask.) What is the pressure of the gas in the flask in kilopascals? 1.00 atm = 101.3 kPa

Solution: The barometeric pressure was 749 mmHg when the open end manometer attached to a flask holding a gas read 13.0 mmHg. (mercury level highest on the side connected to the flask.) What is the pressure of

Problem

The barometeric pressure was 749 mmHg when the open end manometer attached to a flask holding a gas read 13.0 mmHg. (mercury level highest on the side connected to the flask.) What is the pressure of the gas in the flask in kilopascals? 1.00 atm = 101.3 kPa

Solution

We’re being asked to determine the pressure of a gas (in kPa) using an open-end manometer.

A manometer allows you to determine the pressure of a gas (Pgas) sample by using the atmospheric pressure (Patm) and the difference in the height of mercury (h).


Different conditions for an open-end manometer are illustrated below:

When Pgas is pushing the same force as Patm

Pgas=Patm


When Pgas is pushing harder than Patm

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