Problem: Under standard conditions, neopentane is a gas while n-pentane is a liquid. Given that both are non-polar and have identical chemical formulas (C5H12), the reason that n-pentane has a higher boiling point is that 1. it has more H-bonding than the neopentane. 2. it has more C-H bonds that are slightly polar. 3. its straight-chain structure allows for a substantial permanent dipole. 4. its straight-chain structure allows the molecules to have more instantaneous dipoles interacting at close distances. 5. n-pentane has more valence electrons and therefore can form more instantaneous dipoles.

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Problem Details

Under standard conditions, neopentane is a gas while n-pentane is a liquid.

Given that both are non-polar and have identical chemical formulas (C5H12), the reason that n-pentane has a higher boiling point is that

1. it has more H-bonding than the neopentane.

2. it has more C-H bonds that are slightly polar.

3. its straight-chain structure allows for a substantial permanent dipole.

4. its straight-chain structure allows the molecules to have more instantaneous dipoles interacting at close distances.

5. n-pentane has more valence electrons and therefore can form more instantaneous dipoles.

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Based on our data, we think this problem is relevant for Professor Ratliff's class at USF.