🤓 Based on our data, we think this question is relevant for Professor Ratliff's class at USF.
Under standard conditions, neopentane is a gas while n-pentane is a liquid.
Given that both are non-polar and have identical chemical formulas (C5H12), the reason that n-pentane has a higher boiling point is that
1. it has more H-bonding than the neopentane.
2. it has more C-H bonds that are slightly polar.
3. its straight-chain structure allows for a substantial permanent dipole.
4. its straight-chain structure allows the molecules to have more instantaneous dipoles interacting at close distances.
5. n-pentane has more valence electrons and therefore can form more instantaneous dipoles.
Frequently Asked Questions
What scientific concept do you need to know in order to solve this problem?
Our tutors have indicated that to solve this problem you will need to apply the Intermolecular Forces and Physical Properties concept. If you need more Intermolecular Forces and Physical Properties practice, you can also practice Intermolecular Forces and Physical Properties practice problems.
What is the difficulty of this problem?
Our tutors rated the difficulty ofUnder standard conditions, neopentane is a gas while n-penta...as high difficulty.
How long does this problem take to solve?
Our expert Chemistry tutor, Dasha took 4 minutes and 32 seconds to solve this problem. You can follow their steps in the video explanation above.
What professor is this problem relevant for?
Based on our data, we think this problem is relevant for Professor Ratliff's class at USF.