Ch.13 - Chemical KineticsWorksheetSee all chapters
All Chapters
Ch.1 - Intro to General Chemistry
Ch.2 - Atoms & Elements
Ch.3 - Chemical Reactions
BONUS: Lab Techniques and Procedures
BONUS: Mathematical Operations and Functions
Ch.4 - Chemical Quantities & Aqueous Reactions
Ch.5 - Gases
Ch.6 - Thermochemistry
Ch.7 - Quantum Mechanics
Ch.8 - Periodic Properties of the Elements
Ch.9 - Bonding & Molecular Structure
Ch.10 - Molecular Shapes & Valence Bond Theory
Ch.11 - Liquids, Solids & Intermolecular Forces
Ch.12 - Solutions
Ch.13 - Chemical Kinetics
Ch.14 - Chemical Equilibrium
Ch.15 - Acid and Base Equilibrium
Ch.16 - Aqueous Equilibrium
Ch. 17 - Chemical Thermodynamics
Ch.18 - Electrochemistry
Ch.19 - Nuclear Chemistry
Ch.20 - Organic Chemistry
Ch.22 - Chemistry of the Nonmetals
Ch.23 - Transition Metals and Coordination Compounds

Solution: The combustion of propanol, C3H7OH (l), to produce carbon dioxide and water vapor is a highly exothermic process2 C3H7OH (l) + 9 O2 (g) → 6 CO2 (g) + 8 H2O (g)The following data table shows the change in concentration of O 2 over time. Use this data to determine the rate of evolution of water vapor, H2O(g), in the reaction between 10 and 30 seconds.Time in seconds                      Concentration of O2 (M)          0                                           2.48 x 10      -3          10                                          1.26 x 10      -3         20                                          8.98 x 10      -4         30                                          7.17 x 10      -4         40                                          6.32 x 10      -4         50                                          5.98 x 10      -4         60                                          5.71 x 10      -4a. 2.73 x 10 -5b. 2.41 x 10 -5c. 4.83 x 10 -4d. 3.05 x 10 -5e. 6.11 x 10 -4 

Solution: The combustion of propanol, C3H7OH (l), to produce carbon dioxide and water vapor is a highly exothermic process2 C3H7OH (l) + 9 O2 (g) → 6 CO2 (g) + 8 H2O (g)The following data table shows the change

Problem

The combustion of propanol, C3H7OH (l), to produce carbon dioxide and water vapor is a highly exothermic process

2 C3H7OH (l) + 9 O2 (g) → 6 CO2 (g) + 8 H2O (g)

The following data table shows the change in concentration of O 2 over time. Use this data to determine the rate of evolution of water vapor, H2O(g), in the reaction between 10 and 30 seconds.

Time in seconds                      Concentration of O2 (M)

          0                                           2.48 x 10      -3 

         10                                          1.26 x 10      -3

         20                                          8.98 x 10      -4

         30                                          7.17 x 10      -4

         40                                          6.32 x 10      -4

         50                                          5.98 x 10      -4

         60                                          5.71 x 10      -4

a. 2.73 x 10 -5

b. 2.41 x 10 -5

c. 4.83 x 10 -4

d. 3.05 x 10 -5

e. 6.11 x 10 -4

 

Solution

We’re given the following data:

Time (s)

Concentration of O2 (M)

0

2.48 × 10–3

10

1.26 × 10–3

20

8.98 × 10–4

30

7.17 × 10–4

40

6.32 × 10–4

50

5.98 × 10–4

60

5.71 × 10–4


We’re being asked to calculate the rate of formation of H2O(g) between 10 and 30 seconds for the following reaction:

2 C3H7OH(l) + 9 O2(g)  6 CO2(g) + 8 H2O(g)


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