Ch.11 - Liquids, Solids & Intermolecular ForcesWorksheetSee all chapters
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Ch.1 - Intro to General Chemistry
Ch.2 - Atoms & Elements
Ch.3 - Chemical Reactions
BONUS: Lab Techniques and Procedures
BONUS: Mathematical Operations and Functions
Ch.4 - Chemical Quantities & Aqueous Reactions
Ch.5 - Gases
Ch.6 - Thermochemistry
Ch.7 - Quantum Mechanics
Ch.8 - Periodic Properties of the Elements
Ch.9 - Bonding & Molecular Structure
Ch.10 - Molecular Shapes & Valence Bond Theory
Ch.11 - Liquids, Solids & Intermolecular Forces
Ch.12 - Solutions
Ch.13 - Chemical Kinetics
Ch.14 - Chemical Equilibrium
Ch.15 - Acid and Base Equilibrium
Ch.16 - Aqueous Equilibrium
Ch. 17 - Chemical Thermodynamics
Ch.18 - Electrochemistry
Ch.19 - Nuclear Chemistry
Ch.20 - Organic Chemistry
Ch.22 - Chemistry of the Nonmetals
Ch.23 - Transition Metals and Coordination Compounds

How much energy would be absorbed or released by the H 2O in the process.

30 grams H2O(g) at 100°C → 30 grams H2O(l) at 20°C?

1. 16.2 kcal absorbed

2. 16.2 kcal released

3. There would be no transfer of energy due to the first law of thermodynamics

4. 18.6 kcal released

5. 2.4 kcal released



  • For this problem, we need to calculate the total energy released (since it changed from high to low T) for this following changes:

Q for liquid water from 100oC to 20oC (Q1)

Q for steam at 100oC to liquid water at 100oC (Q2)

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