We’re being asked to calculate the rate for HF for the following reaction:
6 NaOH + Al2O3 + 12 HF → 2 Na3AlF6 + 9 H2O
Recall that for a reaction aA → bB, the rate of a reaction is given by:
Δ[A] = change in concentration of reactants or products (in mol/L or M), [A]final – [A]initial
Δt = change in time, tfinal – tinitial
Consider the following reaction:
6NaOH + Al2O3 + 12HF → 2Na3AlF6 + 9H2O
At a given time, water is being produced at a rate of 0.54 M/min for this reaction. What is the corresponding rate for HF during this time?
A. -0.54 M/min
B. -0.72 M/min
C. -0.060 M/min
D. 0.54 M/min
E. 0.72 M/min
F. 0.060 M/min
G. -0.36 M/min
H. 0.36 M/min
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