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# Solution: The work function for chromium metal is 4.37 eV. What wavelength of radiation must be used to eject electrons with a velocity of 2500 km/s?

###### Problem

The work function for chromium metal is 4.37 eV. What wavelength of radiation must be used to eject electrons with a velocity of 2500 km/s?

###### Solution

We’re being asked to determine the wavelength of radiation (light) that must be used to eject electrons from a chromium metal.

When photons with enough energy hit the surface of a metal, electrons are emitted. This phenomenon is known as the Photoelectric Effect.

Total energy (ΔE) in photoelectric effect can be calculated using the following equation:

Where:

Δis the total energy or the energy of the light/photon/radiation and can be calculated using the equation:

$\overline{){\mathbf{∆}}{\mathbf{E}}{\mathbf{=}}{\mathbf{h}}{\mathbf{\nu }}}$

Etotal energy = J
h = Planck’s constant = 6.626x10-34 J
s
ν = frequency = Hz or s-1

Ework function is the work function or threshold frequency of the metal (minimum energy required to remove an electron from the metal)

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