🤓 Based on our data, we think this question is relevant for Professor Fakhreddine's class at TEXAS.

We’re being asked to determine the wavelength of radiation (light) that must be used to eject electrons from a chromium metal.

When photons with enough energy hit the surface of a metal, electrons are emitted. This phenomenon is known as the **Photoelectric Effect**.

**Total energy (****ΔE)** in photoelectric effect can be calculated using the following equation:

$\overline{){\mathbf{\u2206}}{\mathbf{E}}{\mathbf{=}}{{\mathbf{E}}}_{\mathbf{w}\mathbf{o}\mathbf{r}\mathbf{k}\mathbf{}\mathbf{f}\mathbf{u}\mathbf{n}\mathbf{c}\mathbf{t}\mathbf{i}\mathbf{o}\mathbf{n}}{\mathbf{+}}{{\mathbf{E}}}_{\mathbf{K}\mathbf{E}\mathbf{}\mathbf{o}\mathbf{f}\mathbf{}\mathbf{e}\mathbf{l}\mathbf{e}\mathbf{c}\mathbf{t}\mathbf{r}\mathbf{o}\mathbf{n}}}$

**Where:**

• **Δ****E **is* the** total energy or the energy of the light/photon/radiation* and can be calculated using the equation:

$\overline{){\mathbf{\u2206}}{\mathbf{E}}{\mathbf{=}}{\mathbf{h}}{\mathbf{\nu}}}$

E_{total energy} = J

h = Planck’s constant = 6.626x10^{-34} J∙s

ν = frequency = Hz or s^{-1}

• **E _{work function} **is

The work function for chromium metal is 4.37 eV. What wavelength of radiation must be used to eject electrons with a velocity of 2500 km/s?

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Based on our data, we think this problem is relevant for Professor Fakhreddine's class at TEXAS.