Subjects

Sections | |||
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Radioactive Decay | 42 mins | 0 completed | Learn |

Band of Stability | 22 mins | 0 completed | Learn |

Magic Numbers | 10 mins | 0 completed | Learn |

First Order Half Life | 19 mins | 0 completed | Learn |

Additional Practice |
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Alpha Decay |

Beta Decay |

Gamma Emission |

Electron Capture |

Positron Emission |

Nuclear Fission |

Mass Defect |

Nuclear Fusion |

Nuclear Transmutation |

Solution: Calculate the energy change when one 238U nucleus undergoes the reaction:238U + n → 239Pu + 2βThe masses needed are 238U, 238.0508 amu; 239Pu, 239.0522 amu; n, 1.0087 amu. a) -1.1 x 10-12 Jb) -1.5 x 1

Calculate the energy change when one ^{238}U nucleus undergoes the reaction:

^{238}U + n → ^{239}Pu + 2β

The masses needed are ^{238}U, 238.0508 amu; ^{239}Pu, 239.0522 amu; n, 1.0087 amu.

a) -1.1 x 10^{-12} J

b) -1.5 x 10^{-10} J

c) -4.5 x 10^{-10} J

d) +1.5 x 10^{-12} J

e) +3.0 x 10^{-10} J

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