Solution: Calculate the energy change when one 238U nucleus undergoes the reaction:238U + n → 239Pu + 2βThe masses needed are 238U, 238.0508 amu; 239Pu, 239.0522 amu; n, 1.0087 amu. a) -1.1 x 10-12 Jb) -1.5 x 1

Calculate the energy change when one ²³⁸U nucleus undergoes the reaction:

²³⁸U + n → ²³⁹Pu + 2β

The masses needed are ²³⁸U, 238.0508 amu; ²³⁹Pu, 239.0522 amu; n, 1.0087 amu.

a) -1.1 x 10^-12 J

b) -1.5 x 10^-10 J

c) -4.5 x 10^-10 J

d) +1.5 x 10^-12 J

e) +3.0 x 10^-10 J