Chemistry Practice Problems Bohr and Balmer Equations Practice Problems Solution: One of the emission lines of the hydrogen atom has...

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# Solution: One of the emission lines of the hydrogen atom has a wavelength of 93.8 nm. (b) Determine the initial and final values of n associated with this emission.

###### Problem

One of the emission lines of the hydrogen atom has a wavelength of 93.8 nm. (b) Determine the initial and final values of n associated with this emission.

###### Solution

The emitted light has a wavelength of 93.8 nm. When you look at the electromagnetic spectrum, this wavelength lies in the UV region. When the emission is within the UV region we call this the Lyman Series.

Lyman series is referred to when an electron goes from higher numbered shell to the 1st shell.

Based on the Lyman Series, we know now that the final energy level is the first shell where:

nf = 1

We can determine ninitial using the Bohr Equation shown below: View Complete Written Solution

Bohr and Balmer Equations

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