Problem: The ΔH°vap for pure water is 40.65 kJ/mol. Calculate the ΔS°vap for pure water.

FREE Expert Solution

We are asked to calculate the ΔS°vap for pure water.


Recall: 

ΔS°vap =ΔH°vap Tb


Given: 

ΔH°vap = 40.65 kJ/mol

T= 100°C +273.15 = 373.15 K


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Problem Details

The ΔH°vap for pure water is 40.65 kJ/mol. Calculate the ΔS°vap for pure water.

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What scientific concept do you need to know in order to solve this problem?

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