We are asked to calculate the ΔS°_{vap }for pure water.

Recall:

$\overline{){\mathbf{\Delta S}}{{\mathbf{\xb0}}}_{\mathbf{vap}\mathbf{}}{\mathbf{=}}\frac{\mathbf{\Delta H}{\mathbf{\xb0}}_{\mathbf{vap}\mathbf{}}}{{\mathbf{T}}_{\mathbf{b}}}}$

Given:

ΔH°_{vap }= 40.65 kJ/mol

T_{b }= 100°C +273.15 = 373.15 K

The ΔH°vap for pure water is 40.65 kJ/mol. Calculate the ΔS°vap for pure water.

Frequently Asked Questions

What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Entropy concept. You can view video lessons to learn Entropy. Or if you need more Entropy practice, you can also practice Entropy practice problems.