Gay Lussac’s Law:
We can use Gay Lussac’s law as long as the units for the initial and final values are the same.
The given values are:
P1 = 722 mmHg
P2 = 0.95 atm
P2 = 1.07 atm
T1 = 22°C +273.15 = 295.15 K
T2 = ??
We can rearrange the equation to solve for T2:
A flask contains air at 722 mm Hg and 22°C. What would the temperature of the gas be if the pressure is increased to 1.07 atm?
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