Problem: Calculate [H+] for each of the following solutions.[OH-] = 4.8x10-4 M[OH-] = 8.3x10-9 MA solution in which [OH-] is 140 times greater than [H+].

FREE Expert Solution

In this problem, we are asked to calculate for [H+] for each of the following solutions.

A. [OH-] = 4.8x10-4 M

• pOH:

$\overline{){\mathbf{pOH}}{\mathbf{=}}{\mathbf{-}}{\mathbf{log}}\mathbf{\left[}{\mathbf{OH}}^{\mathbf{-}}\mathbf{\right]}}\phantom{\rule{0ex}{0ex}}\mathbf{pOH}\mathbf{=}\mathbf{-}\mathbf{log}\mathbf{\left(}\mathbf{4}\mathbf{.}\mathbf{8}\mathbf{×}{\mathbf{10}}^{\mathbf{-}\mathbf{4}}\mathbf{\right)}$

pOH = 3.32 M

Problem Details

Calculate [H+] for each of the following solutions.

[OH-] = 4.8x10-4 M

[OH-] = 8.3x10-9 M

A solution in which [OH-] is 140 times greater than [H+].