Problem: Predict the ΔHrxn for the following reaction: Rb(g) + Na+(g) → Rb+(g) + Na(g).a) ΔHrxn < 0 because the IE1 for Rb is less than the IE1 for Nab) ΔHrxn > 0 because the IE1 for Rb is less than the IE1 for Nac) ΔHrxn < 0 because the IE1 for Na is less than the IE1 for Rbd) ΔHrxn < 0 because the IE1 for Na+ is less than the IE1 for Rb+e) ΔHrxn > 0 because the IE1 for Na+ is less than the IE1 for Rb+

FREE Expert Solution

Given reaction: Rb(g) + Na+(g)  Rb+(g) + Na(g).

Ionization enthalpy or ionization energy is the amount of energy required to remove most loosely bound electron from the valence shell of an isolated gaseous atom.

  • IE1 of Rb: 403 kJ/mol
  • IE1 of Na: 496 kJ/mol

ΔHrxn is calculated as:

Hrxn =Hproducts-Hreactants


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Problem Details

Predict the ΔHrxn for the following reaction: Rb(g) + Na+(g) → Rb+(g) + Na(g).

a) ΔHrxn < 0 because the IE1 for Rb is less than the IE1 for Na

b) ΔHrxn > 0 because the IE1 for Rb is less than the IE1 for Na

c) ΔHrxn < 0 because the IE1 for Na is less than the IE1 for Rb

d) ΔHrxn < 0 because the IE1 for Na+ is less than the IE1 for Rb+

e) ΔHrxn > 0 because the IE1 for Na+ is less than the IE1 for Rb+

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