Problem: Construct the octahedral crystal-field splitting diagram for the metal in each species. a) V(H2O)63+ b) Co(CN)63- c) Mn(H2O)62+

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Octahedral crystal-field splitting diagram → d-orbital electrons

  • high-spin - electrons can occupy the upper level (eg) 
  • low-spin - electrons can pair up with the electrons on the lower level (t2g) 


Recall that:

  • weak field ligands → high spin  lowΔ or crystal field splitting energy values
  • strong field ligands → low spin  highΔ or crystal field splitting energy values


a) V(H2O)63+

  • Neutral state: V: [Ar] 4s23d3
    • Nearest noble gas before V is Ar
  • Excited state: 

▪ charge = +3: means that it lost 3 electrons:
 subtract the electrons from the highest numbered orbital or higher energy orbital: 4s first then 3d 

V3+:  [Ar]4s23d3-1

V3+: [Ar] 3d2

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Problem Details

Construct the octahedral crystal-field splitting diagram for the metal in each species. 

a) V(H2O)63+ 

b) Co(CN)63- 

c) Mn(H2O)62+

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Based on our data, we think this problem is relevant for Professor Laskin & Skrynnikov's class at PURDUE.