Problem: Rank acetic acid (HC2H3O2), hydrocyanic acid (HOCN), and hydrofluoric acid (HF) in order of increasing strength.Acid                             KaHC2H3O2                  1.8 × 10–5HOCN                        3.5 × 10–4HF                              6.8 × 10–4A) HC2H3O2 < HOCN < HFB) HOCN < HC2H3O2 < HFC) HOCN < HF < HC2H3O2D) HF < HOCN < HC2H3O2E) HF < HC2H3O2 < HOCN

FREE Expert Solution

For this problem, we have to rank acetic acid (HC2H3O2), hydrocyanic acid (HOCN), and hydrofluoric acid (HF) in order of increasing strength.

  • For a weak acid HA, the acid-base reaction will appear as:

HA (aq) + H2O (l) ⇌ H3O+ (aq) + A- (aq)

  • Ka expressions can be written as:

Ka = [H+][A-][HA]

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Problem Details

Rank acetic acid (HC2H3O2), hydrocyanic acid (HOCN), and hydrofluoric acid (HF) in order of increasing strength.

Acid                             Ka
HC2H3O2                  1.8 × 10–5
HOCN                        3.5 × 10–4
HF                              6.8 × 10–4

A) HC2H3O2 < HOCN < HF

B) HOCN < HC2H3O2 < HF

C) HOCN < HF < HC2H3O2

D) HF < HOCN < HC2H3O2

E) HF < HC2H3O2 < HOCN

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