# Problem: The rate of disappearance of HBr in the gas phase reaction2HBr (g) → H 2 (g) + Br2 (g) is 0.602 M s-1 at 150°C. The rate of appearance of Br2 is _____ M s-1 . a) 1.20b) 0.602c) 0.0906d) 0.301e) 0.151

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###### FREE Expert Solution

We’re being asked to calculate the rate of appearance of Br2 for the following reaction:

2HBr (g) → H 2 (g) $+$ Br2 (g)

Recall that for a reaction aA  bB, the rate of a reaction is given by:

$\overline{){\mathbf{Rate}}{\mathbf{=}}{\mathbf{-}}\frac{\mathbf{1}}{\mathbf{a}}\frac{\mathbf{\Delta }\mathbf{\left[}\mathbf{A}\mathbf{\right]}}{\mathbf{\Delta t}}{\mathbf{=}}\frac{\mathbf{1}}{\mathbf{b}}\frac{\mathbf{\Delta }\mathbf{\left[}\mathbf{B}\mathbf{\right]}}{\mathbf{\Delta t}}}$

where:

Δ[A] = change in concentration of reactants or products (in mol/L or M)

Δt = change in time ###### Problem Details

The rate of disappearance of HBr in the gas phase reaction

2HBr (g) → H 2 (g) $+$ Br2 (g) is 0.602 M s-1 at 150°C. The rate of appearance of Br2 is _____ M s-1

a) 1.20

b) 0.602

c) 0.0906

d) 0.301

e) 0.151