Chemistry Practice Problems Weak Acid Strong Base Titrations Practice Problems Solution: 1.00 g CH3NH3Cl (MW = 67.52 g/mol) and 1.00 g Ba(O...

Solution: 1.00 g CH3NH3Cl (MW = 67.52 g/mol) and 1.00 g Ba(OH) 2∙8H2O (a strong base, MW = 315.47 g/mol) are added to 80 mL of water and dissolved. The resulting solution is diluted to 100 mL with water at 25°C.Is this an acidic or basic buffer? Justify your answer.A. neutralB. acidic neutralC. basic neutral

Problem

1.00 g CH3NH3Cl (MW = 67.52 g/mol) and 1.00 g Ba(OH) 2∙8H2O (a strong base, MW = 315.47 g/mol) are added to 80 mL of water and dissolved. The resulting solution is diluted to 100 mL with water at 25°C.

Is this an acidic or basic buffer? Justify your answer.

A. neutral

B. acidic neutral

C. basic neutral

Solution

We are being asked to determine if the resulting solution is an acidic or basic buffer.


We will calculate the pH of the solution at the equivalence point using the following steps:

Step 1. Write the chemical equation for the reaction between CH3NH3Cl and Ba(OH)2.
Step 2. Calculate the initial amounts of CH3NH3Cl and Ba(OH)2 in moles before the reaction happens.
Step 3. Construct an ICF Chart.
Step 4. Calculate pH.


Step 1. Write the chemical equation for the reaction between CH3NH3Cl and Ba(OH)2.

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