Problem: What is Kb for pyridine (C5H5N) if Ka for its conjugate acid is 5.9 x 10-6 at 25°C?A) 1.7 x 10-9 B) 5.9 x 108C) 1 x 1014D) 1.7 x 1019 

FREE Expert Solution

We are asked to find Kb for C5H5N given that the Ka of its conjugate acid (C5H5NH+) is 5.9x10-6

The dissociation of C5H5NH+ with water will appear as:

C5H5NH(aq) + H2O (l)  ⇌ C5H5NH (aq) + OH- (aq)                       Ka = 5.9x10-6

Recall that Ka and Kb are connected by the autoionization constant of water (Kwby the following equation:

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Problem Details

What is Kb for pyridine (C5H5N) if Ka for its conjugate acid is 5.9 x 10-6 at 25°C?

A) 1.7 x 10-9 

B) 5.9 x 108

C) 1 x 1014

D) 1.7 x 1019 

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