# Problem: At a certain temperature, Kp for the reaction,Br2(g) &lt;=&gt; 2 Br(g) is 3,498.Calculate the value of Kp for the reaction,1/2 Br2(g) ) &lt;=&gt; Br(g)

###### FREE Expert Solution

We’re being asked to determine the equilibrium constant at 458 ˚C for this reaction:

1/2 Br2(g) Br(g)

Given another reaction with it's Kp

Br2(g) 2 Br(g) is 3,498

Recall that the equilibrium constant is the ratio of the products and reactants

We use Kp when dealing with pressure and Kc when dealing with concentration:

$\overline{){{\mathbf{K}}}_{{\mathbf{p}}}{\mathbf{=}}\frac{{\mathbf{P}}_{\mathbf{products}}}{{\mathbf{P}}_{\mathbf{reactants}}}}$     $\overline{){{\mathbf{K}}}_{{\mathbf{c}}}{\mathbf{=}}\frac{\mathbf{\left[}\mathbf{products}\mathbf{\right]}}{\mathbf{\left[}\mathbf{reactants}\mathbf{\right]}}}$

Note that solid and liquid compounds are ignored in the equilibrium expression.

###### Problem Details

At a certain temperature, Kp for the reaction,

Br2(g) <=> 2 Br(g) is 3,498.

Calculate the value of Kp for the reaction,

1/2 Br2(g) ) <=> Br(g)