We’re being asked to determine [H3O+] and [OH-] of an acidic solution at 40 °C if the value of Kw is 2.92 × 10–14.
Recall that Kw is the autoionization constant of water, and is given by:
At 40 °C, the value of Kw = 2.92 × 10–14. An acidic solution at 40 °C will therefore have:
A. [H3O+] > [OH–] and [H3O+] = 1.70 × 10–7 M
B. [H3O+] > [OH–] and [H3O+] > 1.70 × 10–7 M
C [H3O+] > [OH–] and [H3O+] = 2.96 × 10–7 M
D. [H3O+] = [OH–] and [OH–] = 1.70 × 10–7 M
E. [H3O+] < [OH–] and [OH–] > 1.70 × 10–7 M
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