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Ammonia, NH3, reacts with the hypochlorite ion, OCl - to produce hydrazine, N2H4.
2NH3 + OCl – → N2H4 + Cl – + H2O
What is the percent yield of hydrazine when 5.85 g of NH 3 reacts with excess hypochlorite to produce 2.60 g of N2H4? Molar mass: NH3 = 17.031 g/mol; N2H4= 32.046 g/mol
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Based on our data, we think this problem is relevant for Professor McCord's class at TEXAS.