We are asked to calculate for the **percent by mass (mass %) of oxygen **in** C _{14}H_{19}NO**

$\overline{){M}{a}{s}{s}{}{P}{e}{r}{c}{e}{n}{t}{}{=}{}\frac{Massofelement}{Totalmassofcompound}{\times}{}{100}{\%}}$

For the **percent by mass O,** we’re going to rewrite the equation as:

$\overline{){M}{a}{s}{s}{}{P}{e}{r}{c}{e}{n}{t}{}{O}{=}{}\frac{MassofO}{massof{C}_{14}{H}_{19}N{O}_{2}}{\times}{}{100}{\%}}$

What is the mass percent of oxygen in C_{14}H_{19}NO_{2}?

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