Ch.7 - Quantum MechanicsWorksheetSee all chapters
All Chapters
Ch.1 - Intro to General Chemistry
Ch.2 - Atoms & Elements
Ch.3 - Chemical Reactions
BONUS: Lab Techniques and Procedures
BONUS: Mathematical Operations and Functions
Ch.4 - Chemical Quantities & Aqueous Reactions
Ch.5 - Gases
Ch.6 - Thermochemistry
Ch.7 - Quantum Mechanics
Ch.8 - Periodic Properties of the Elements
Ch.9 - Bonding & Molecular Structure
Ch.10 - Molecular Shapes & Valence Bond Theory
Ch.11 - Liquids, Solids & Intermolecular Forces
Ch.12 - Solutions
Ch.13 - Chemical Kinetics
Ch.14 - Chemical Equilibrium
Ch.15 - Acid and Base Equilibrium
Ch.16 - Aqueous Equilibrium
Ch. 17 - Chemical Thermodynamics
Ch.18 - Electrochemistry
Ch.19 - Nuclear Chemistry
Ch.20 - Organic Chemistry
Ch.22 - Chemistry of the Nonmetals
Ch.23 - Transition Metals and Coordination Compounds

Solution:  What is the largest wavelength in the Balmer series?

Problem

 What is the largest wavelength in the Balmer series?

Solution

We can determine the largest wavelength, λmax in the Balmer series using the Balmer Equation shown below:


1λmax=R×1nf2-1ni2

where: 

λmax = wavelength, m corresponding to lowest principal initial energy level,   ↓nλ

R = 1.0974 x 107m-1 (Rydberg Constant)      **value can be found in textbooks or online 
ni = initial principal energy level  
nf = final principal energy level = 2 for Balmer Series 


Recall that for the Balmer series the final principal energy level nf is always = 2. 

The largest wavelength, λmax will be the maximum wavelength corresponding to the lowest initial energy level, ni = 3  for a Hydrogen atom.  Recall that the lowest transition releases the lowest energy, E and will occur from n = 2 to n = 3 (next energy level).  

Energy, E is inversely proportional to the wavelength, λ↓E, ↓niλ


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