What is the smallest wavelength in the Balmer's series?

We can determine the **smallest wavelength, λ_{min} **in the

$\overline{)\frac{1}{{\lambda}_{min}}{=}{R}{\times}\left(\frac{1}{{{n}_{f}}^{2}}-\frac{{\displaystyle 1}}{{\displaystyle {{n}_{i}}^{2}}}\right)}\phantom{\rule{0ex}{0ex}}$

*where: *

**λ _{min}**

R = 1.0974 x 10^{7}m^{-1} (Rydberg Constant) ***value can be found in textbooks or online *n

Recall that for the** ****Balmer series the final principal energy level n _{f} is always = 2.**

The smallest wavelength, ** λ_{min}** will be the

Recall that the **highest transition** releases the** highest energy, E.**

**Energy, E** is **inversely proportional** to the **wavelength, ****λ**:

Bohr and Balmer Equations

Bohr and Balmer Equations

Bohr and Balmer Equations

Bohr and Balmer Equations

Bohr and Balmer Equations