Ch. 17 - Chemical ThermodynamicsWorksheetSee all chapters
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Ch.1 - Intro to General Chemistry
Ch.2 - Atoms & Elements
Ch.3 - Chemical Reactions
BONUS: Lab Techniques and Procedures
BONUS: Mathematical Operations and Functions
Ch.4 - Chemical Quantities & Aqueous Reactions
Ch.5 - Gases
Ch.6 - Thermochemistry
Ch.7 - Quantum Mechanics
Ch.8 - Periodic Properties of the Elements
Ch.9 - Bonding & Molecular Structure
Ch.10 - Molecular Shapes & Valence Bond Theory
Ch.11 - Liquids, Solids & Intermolecular Forces
Ch.12 - Solutions
Ch.13 - Chemical Kinetics
Ch.14 - Chemical Equilibrium
Ch.15 - Acid and Base Equilibrium
Ch.16 - Aqueous Equilibrium
Ch. 17 - Chemical Thermodynamics
Ch.18 - Electrochemistry
Ch.19 - Nuclear Chemistry
Ch.20 - Organic Chemistry
Ch.22 - Chemistry of the Nonmetals
Ch.23 - Transition Metals and Coordination Compounds

Solution: Calculate the change in internal energy for a gas using the first law of thermodynamics. The gas transfers 485 J of energy as heat to the surroundings.Pext = 1.01 x 105 PaV1 = 2.30 LV2 = 2.05 L

Solution: Calculate the change in internal energy for a gas using the first law of thermodynamics. The gas transfers 485 J of energy as heat to the surroundings.Pext = 1.01 x 105 PaV1 = 2.30 LV2 = 2.05 L

Problem

Calculate the change in internal energy for a gas using the first law of thermodynamics. The gas transfers 485 J of energy as heat to the surroundings.

Pext = 1.01 x 105 Pa

V1 = 2.30 L

V2 = 2.05 L

Solution

For a gas, the internal energy (ΔE or ΔUof a system can be calculated from the heat and work of the system.

The relationship between internal energy, heat, and work is shown in the following equation:

E=q+w

 Where

ΔE = internal energy, J

q = heat, J

w = work, J


To solve for Internal Energy, we have to:

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