# Problem: Calculate the quantity of energy produced per mole of U-235 (atomic mass = 235.043922 amu) for the neutron-induced fission of U-235 to produce Te-137 (atomic mass = 136.9253 amu) and Zr-97 (atomic mass = 96.910950 amu). (Note: the products produced will include two neutrons.)

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###### FREE Expert Solution

We’re being asked to calculate the energy produced for the following nuclear reaction:

${}_{\mathbf{92}}{}^{\mathbf{235}}\mathbf{U}\mathbf{+}{}_{\mathbf{0}}{}^{\mathbf{1}}\mathbf{n}\mathbf{\to }{}_{\mathbf{52}}{}^{\mathbf{137}}\mathbf{Te}\mathbf{+}{}_{\mathbf{40}}{}^{\mathbf{97}}\mathbf{Zr}\mathbf{+}\mathbf{2}{}_{\mathbf{0}}{}^{\mathbf{1}}\mathbf{n}$

To calculate the energy released for the reaction, we’re going to use the following steps:

Step 1: Calculate the mass defect (Δm).
Step 2: Calculate the mass defect (Δm) in kg.
Step 3: Calculate the energy released (E).

Step 1: Calculate the mass defect (Δm).

Given: ###### Problem Details

Calculate the quantity of energy produced per mole of U-235 (atomic mass = 235.043922 amu) for the neutron-induced fission of U-235 to produce Te-137 (atomic mass = 136.9253 amu) and Zr-97 (atomic mass = 96.910950 amu). (Note: the products produced will include two neutrons.)