Ch.3 - Chemical ReactionsWorksheetSee all chapters
All Chapters
Ch.1 - Intro to General Chemistry
Ch.2 - Atoms & Elements
Ch.3 - Chemical Reactions
BONUS: Lab Techniques and Procedures
BONUS: Mathematical Operations and Functions
Ch.4 - Chemical Quantities & Aqueous Reactions
Ch.5 - Gases
Ch.6 - Thermochemistry
Ch.7 - Quantum Mechanics
Ch.8 - Periodic Properties of the Elements
Ch.9 - Bonding & Molecular Structure
Ch.10 - Molecular Shapes & Valence Bond Theory
Ch.11 - Liquids, Solids & Intermolecular Forces
Ch.12 - Solutions
Ch.13 - Chemical Kinetics
Ch.14 - Chemical Equilibrium
Ch.15 - Acid and Base Equilibrium
Ch.16 - Aqueous Equilibrium
Ch. 17 - Chemical Thermodynamics
Ch.18 - Electrochemistry
Ch.19 - Nuclear Chemistry
Ch.20 - Organic Chemistry
Ch.22 - Chemistry of the Nonmetals
Ch.23 - Transition Metals and Coordination Compounds

Solution: Ammonia, NH3, reacts with hypochlorite ion, OCI -, to produce hydrazine N2H4. How many moles of hydrazine are produced from 5.85 mol of ammonia if the reaction has a 78.2% yield?2 NH3 + OCl- → N2H4 + Cl- + H2Oa) 2.29 molb) 2.92 molc) 4.57 mold) 9.15 mol

Solution: Ammonia, NH3, reacts with hypochlorite ion, OCI -, to produce hydrazine N2H4. How many moles of hydrazine are produced from 5.85 mol of ammonia if the reaction has a 78.2% yield?2 NH3 + OCl- → N2H4 +

Problem

Ammonia, NH3, reacts with hypochlorite ion, OCI -, to produce hydrazine N2H4. How many moles of hydrazine are produced from 5.85 mol of ammonia if the reaction has a 78.2% yield?

2 NH3 + OCl- → N2H4 + Cl- + H2O

a) 2.29 mol

b) 2.92 mol

c) 4.57 mol

d) 9.15 mol