Problem: Given that Kb for ammonia is 1.8x10-5 and that for hydroxylamine is 1.1x10-8, calculate Ka value for H3NOH+.

🤓 Based on our data, we think this question is relevant for Professor Woerner's class at DUKE.

FREE Expert Solution

ammonia → NH3

NH3(aq) + H2O(aq) → NH4+(aq) + OH-(aq)


hydroxylamine → H2NOH

H2NOH(aq) + H2O(aq)H3NOH+(aq) + OH-(aq)


Kb for hydroxylamine is given:  Kb = 1.1x10-8

Ka and Kb are connected by the following equation:

Kw=Ka·Kb

Where Kw is the autoionization constant of water:

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Problem Details

Given that Kb for ammonia is 1.8x10-5 and that for hydroxylamine is 1.1x10-8, calculate Ka value for H3NOH+.

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Based on our data, we think this problem is relevant for Professor Woerner's class at DUKE.