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ammonia → NH3
NH3(aq) + H2O(aq) → NH4+(aq) + OH-(aq)
hydroxylamine → H2NOH
H2NOH(aq) + H2O(aq) → H3NOH+(aq) + OH-(aq)
Kb for hydroxylamine is given: Kb = 1.1x10-8
Ka and Kb are connected by the following equation:
Where Kw is the autoionization constant of water:
Given that Kb for ammonia is 1.8x10-5 and that for hydroxylamine is 1.1x10-8, calculate Ka value for H3NOH+.
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