Problem: Consider a 0.10 M solution of a weak polyprotic acid (H2 A) with the possible values of Ka1  and Ka2  given below. Calculate the contributions to [H3O+] from each ionization step.Ka1  = 1.0 10 - 4 ; Ka2  = 1.0 10 - 5

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We’re given a weak diprotic acid and we are asked to calculate the contributions to [H3O+] from each ionization step.


Given:

Ka1 = 1.0 x10-4

1st equilibrium reaction:                H2A(aq) + H2O(l) → HA­-(aq)H3O+(aq

Ka2 = 1.0 x10-5

2nd equilibrium reaction:               HA-(aq) + H2O(l) → A2­-(aq)H3O+(aq)

H3O+(aq) is also produced from the 2nd equilibrium reaction

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Problem Details

Consider a 0.10 M solution of a weak polyprotic acid (H2 A) with the possible values of Ka1  and Ka2  given below. Calculate the contributions to [H3O+] from each ionization step.

Ka1  = 1.0 10 - 4 ; Ka2  = 1.0 10 - 5

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