🤓 Based on our data, we think this question is relevant for Professor Chamberlain's class at UCD.

*Recall the equation for a first-order half-life:*

$\overline{){{\mathbf{t}}}_{\raisebox{1ex}{$\mathbf{1}$}\!\left/ \!\raisebox{-1ex}{$\mathbf{2}$}\right.}{\mathbf{=}}\frac{\mathbf{ln}\mathbf{}\mathbf{2}}{\mathbf{k}}}$

*t _{1/2} = 3.00 hr*

**Calculate k:**

$\overline{){{\mathbf{t}}}_{\raisebox{1ex}{$\mathbf{1}$}\!\left/ \!\raisebox{-1ex}{$\mathbf{2}$}\right.}{\mathbf{=}}\frac{\mathbf{ln}\mathbf{}\mathbf{2}}{\mathbf{k}}}\phantom{\rule{0ex}{0ex}}\mathbf{k}\mathbf{=}\frac{\mathbf{ln}\mathbf{}\mathbf{2}}{{\mathbf{t}}_{{\displaystyle \raisebox{1ex}{$\mathbf{1}$}\!\left/ \!\raisebox{-1ex}{$\mathbf{2}$}\right.}}}\phantom{\rule{0ex}{0ex}}\mathbf{k}\mathbf{=}\frac{\mathbf{ln}\mathbf{}\mathbf{2}}{\mathbf{3}\mathbf{.}\mathbf{00}\mathbf{}\overline{)\mathbf{hr}}}\mathbf{\times}\frac{\mathbf{1}\mathbf{}\overline{)\mathbf{hr}}}{\mathbf{60}\mathbf{}\overline{)\mathbf{min}}}\mathbf{\times}\frac{\mathbf{1}\mathbf{}\overline{)\mathbf{min}}}{\mathbf{60}\mathbf{}\mathbf{s}}$

**k = 6.418x10 ^{-5} s^{-1}**

**Calculate rate:**

A certain radioactive nuclide has a half-life of 3.00 hours.

b. Calculate the decay rate in decays/s for 1.000 mole of this nuclide.

Frequently Asked Questions

What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the First Order Half Life concept. You can view video lessons to learn First Order Half Life. Or if you need more First Order Half Life practice, you can also practice First Order Half Life practice problems.

What professor is this problem relevant for?

Based on our data, we think this problem is relevant for Professor Chamberlain's class at UCD.

What textbook is this problem found in?

Our data indicates that this problem or a close variation was asked in Chemistry: An Atoms First Approach - Zumdahl 2nd Edition. You can also practice Chemistry: An Atoms First Approach - Zumdahl 2nd Edition practice problems.